document.write( "Question 908430: Please, help me solved this quadratic equation: x²+12x+36=9 \n" ); document.write( "
Algebra.Com's Answer #551026 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
x²+12x+27=0
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"x%5E2%2B12%2Ax%2B27=0\" ( notice \"a=1\", \"b=12\", and \"c=27\")
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\n" ); document.write( " \"x+=+%28-12+%2B-+sqrt%28+%2812%29%5E2-4%2A1%2A27+%29%29%2F%282%2A1%29\" Plug in a=1, b=12, and c=27
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\n" ); document.write( " \"x+=+%28-12+%2B-+sqrt%28+144-4%2A1%2A27+%29%29%2F%282%2A1%29\" Square 12 to get 144
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\n" ); document.write( " \"x+=+%28-12+%2B-+sqrt%28+144%2B-108+%29%29%2F%282%2A1%29\" Multiply \"-4%2A27%2A1\" to get \"-108\"
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\n" ); document.write( " \"x+=+%28-12+%2B-+sqrt%28+36+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%28-12+%2B-+6%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%28-12+%2B-+6%29%2F2\" Multiply 2 and 1 to get 2
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"x+=+%28-12+%2B+6%29%2F2\" or \"x+=+%28-12+-+6%29%2F2\"
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\n" ); document.write( " Lets look at the first part:
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\n" ); document.write( " \"x=%28-12+%2B+6%29%2F2\"
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\n" ); document.write( " \"x=-6%2F2\" Add the terms in the numerator
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\n" ); document.write( " \"x=-3\" Divide
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\n" ); document.write( " So one answer is
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\n" ); document.write( " \"x=-3\"
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\n" ); document.write( " Now lets look at the second part:
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\n" ); document.write( " \"x=%28-12+-+6%29%2F2\"
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\n" ); document.write( " \"x=-18%2F2\" Subtract the terms in the numerator
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\n" ); document.write( " \"x=-9\" Divide
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\n" ); document.write( " So another answer is
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\n" ); document.write( " \"x=-9\"
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\n" ); document.write( " So our solutions are:
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\n" ); document.write( " \"x=-3\" or \"x=-9\"
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