document.write( "Question 908408: . Find the equation of a line described as follows and express your answer in point-slope form, slope-intercept form, and standard form
\n" ); document.write( "Find the equation of the line perpendicular to the line y+3=3(x-5) that passes through the point (-4, -6)
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Algebra.Com's Answer #551023 by lwsshak3(11628)\"\" \"About 
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Find the equation of a line described as follows and express your answer in point-slope form, slope-intercept form, and standard form
\n" ); document.write( "Find the equation of the line perpendicular to the line y+3=3(x-5) that passes through the point (-4, -6)
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\n" ); document.write( "y+3=3(x-5)
\n" ); document.write( "slope,m=3
\n" ); document.write( "slope of perpendicular line=-1/3 (negative reciprocal
\n" ); document.write( "..
\n" ); document.write( "slope-intercept form: y=m+b, m=slope, b=y-intercept
\n" ); document.write( "y=-x/3+b
\n" ); document.write( "solve for b using coordinates of given point (-4,-6) on the line
\n" ); document.write( "-6=-(-4)/3+b
\n" ); document.write( "-18=4+3b
\n" ); document.write( "b=-22/3
\n" ); document.write( "y=-x/3-22/3 (slope-intercept form)
\n" ); document.write( "..
\n" ); document.write( "Point-slope form:(y1-y2)=m(x1-x2)
\n" ); document.write( "(y-(-6))=m(x-(-4))
\n" ); document.write( "(y+6)=-(1/3)(x+4)
\n" ); document.write( "..
\n" ); document.write( "Standard form:ax+by=c
\n" ); document.write( "y=-(x/3-22/3
\n" ); document.write( "3y=-x-22
\n" ); document.write( "x+3y=-22 \n" ); document.write( "
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