document.write( "Question 76857: please help me solve the following problem.
\n" );
document.write( " problem:Determine the domain of each function.
\n" );
document.write( "i)f(x)=x+2/x
\n" );
document.write( "ii) f(x)=2x+1/sq.root of x-1
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #55097 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! please help me solve the following problem. \n" ); document.write( " problem:Determine the domain of each function. \n" ); document.write( "i)f(x)=x+2/x \n" ); document.write( "ii) f(x)=2x+1/sq.root of x-1 \n" ); document.write( " \n" ); document.write( "Domain is what the x's are allowed to be. \n" ); document.write( "For i, denominators can be anything except for 0. Therefore, the domain for i is {x|x not=0} <--set builder notation \n" ); document.write( "(-infinity,0)U(0,infinity) <--interval notation \n" ); document.write( ": \n" ); document.write( "For ii, denominators can be anything except 0, but even roots have to be positive or 0 on the inside. In this case the denominator is a square root, so what is inside of the square root has to be positive and not equal to 0. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Therefore, the domain of ii is {x|x>1} set builder notation \n" ); document.write( "(1,infinity) set builder notation. \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |