document.write( "Question 76857: please help me solve the following problem.
\n" ); document.write( " problem:Determine the domain of each function.
\n" ); document.write( "i)f(x)=x+2/x
\n" ); document.write( "ii) f(x)=2x+1/sq.root of x-1
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Algebra.Com's Answer #55097 by funmath(2933)\"\" \"About 
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please help me solve the following problem.
\n" ); document.write( " problem:Determine the domain of each function.
\n" ); document.write( "i)f(x)=x+2/x
\n" ); document.write( "ii) f(x)=2x+1/sq.root of x-1
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\n" ); document.write( "Domain is what the x's are allowed to be.
\n" ); document.write( "For i, denominators can be anything except for 0. Therefore, the domain for i is {x|x not=0} <--set builder notation
\n" ); document.write( "(-infinity,0)U(0,infinity) <--interval notation
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\n" ); document.write( "For ii, denominators can be anything except 0, but even roots have to be positive or 0 on the inside. In this case the denominator is a square root, so what is inside of the square root has to be positive and not equal to 0.
\n" ); document.write( "\"x-1%3E0\"
\n" ); document.write( "\"x-1%2B1%3E0%2B1\"
\n" ); document.write( "\"x%3E1\"
\n" ); document.write( "Therefore, the domain of ii is {x|x>1} set builder notation
\n" ); document.write( "(1,infinity) set builder notation.
\n" ); document.write( "Happy Calculating!!!
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