document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908338>Question 908338</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Theodore needs to mix a 20% acid solution with a 60% acid solution to create 200 millileters of a 24% solution. How many millileters of each solution must Theodore use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550965 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550965\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Theodore needs to mix a 20% acid solution with a 60% acid solution to create 200 millileters of a 24% solution. How many millileters of each solution must Theodore use?<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.20x + 0.60(200-x) = 0.24*200<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "20x + 60*200 - 60x = 24*200<BR>\n" );
document.write( "-40x = -36*200<BR>\n" );
document.write( "----<BR>\n" );
document.write( "x = 5*36<BR>\n" );
document.write( "x = 180 ml (amt. of 20% solution needed)<BR>\n" );
document.write( "200-x = 20 ml (amt. of 60% solution needed)<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "---------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );