document.write( "Question 76858This question is from textbook Beginning Algebra
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document.write( ": Please help!!! I have tried solving the following problems, but can't seem to understand. Whatever assistance anyone can provide will be greatly appreciated. Thanks in advance.\r
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document.write( "PG. 575
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document.write( "Using the factoring method, solve for the roots of each quadratic equation. Be sure to place your equation in standard form before factoring.\r
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document.write( "(14.)x^2 + 3x - 40 = 0\r
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document.write( "PG. 588
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document.write( "Solve using the quadratic formula. If there are no real roots, say so.\r
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document.write( "(20.) 3x^2 - 4x + 2 = 0 \n" );
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Algebra.Com's Answer #55095 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! X^2+3X-40=0 \n" ); document.write( "(X-5)(X+8)=0 \n" ); document.write( "X-5=0 \n" ); document.write( "X=5 ANSWER. \n" ); document.write( "X+8=0 \n" ); document.write( "X=-8 ANSWER. \n" ); document.write( "------------------------------------------------------------ \n" ); document.write( "3X^2-4X+2=0 \n" ); document.write( "USING THE QUADRATIC EQUATION WE GET: \n" ); document.write( " \n" ); document.write( "X=(4+-SQRT[-4*-4-4*3*2])/2*3 \n" ); document.write( "X=(4+-SQRT[16-24])/6 \n" ); document.write( "X=(4+-SQRT-8)/6 BECAUSE THERE IS A NEGATIVE NUMBER UNDER THE SQRT SIGN THE ANSWERS WILL NOT BE REAL ROOTS. THUS \n" ); document.write( "X=(4+-2.83i)/6 \n" ); document.write( "X=4/6+2.83i/6 \n" ); document.write( "X=2/3+,47i ANSWER. \n" ); document.write( "X=(4-2.38i)/6 \n" ); document.write( "X=4/6-2.38i/6 \n" ); document.write( "X=2/3-.47i ANSWER.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |