document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908217>Question 908217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ram and Sham have a sum of 220 Rs together.if 30% of Rams amount is equal to 75% of Sham's amount.Calculate the amount get by sham </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550923 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .3R = .75S<BR>\n" );
document.write( "Multiply each side by 1<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, in order to isolate S as a whole.<BR>\n" );
document.write( ".4R = S<BR>\n" );
document.write( "R + S = 220<BR>\n" );
document.write( "Now substitute the known value of S from the equation above into the bottom equation.<BR>\n" );
document.write( "R + S = 220<BR>\n" );
document.write( "R + (.4R) = 220<BR>\n" );
document.write( "1.4R = 220<BR>\n" );
document.write( "Divide each side by 1.4<BR>\n" );
document.write( "R = 157.14 Rs<BR>\n" );
document.write( "Therefore, S = 62.86 Rs<BR>\n" );
document.write( "That came out strange numbers, but they add to 220 and fulfill the requirements above.   </SPAN>\n" );
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