document.write( "Question 908236: In a particular quadrilateral, two angles have the same measure. A third angle is 10 degrees more than the measure of each of the equal angles. The fourth angle is half the measure of each of the equal angles. Find the measure of the angles knowing a quadrilateral has 4 angles whose sum is 360 degrees.
\n" ); document.write( "I have:\r
\n" ); document.write( "\n" ); document.write( " x = angle #1
\n" ); document.write( " x = angle #2
\n" ); document.write( " 10+ 2x = angle #3
\n" ); document.write( " 2x-1/2 = angle #4\r
\n" ); document.write( "\n" ); document.write( "x+x+10+2x+2x-1/2=360 \r
\n" ); document.write( "\n" ); document.write( "6x+10-.5 = 360\r
\n" ); document.write( "\n" ); document.write( "6x+9.5 = 360\r
\n" ); document.write( "\n" ); document.write( "6x=350.5\r
\n" ); document.write( "\n" ); document.write( "x=58.42 which is not correct; I'm not sure where I'm going wrong with this one.
\n" ); document.write( "Thank you for any help you can give me. It is very much appreciated! \n" ); document.write( "

Algebra.Com's Answer #550912 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!
x = angle #1
\n" ); document.write( " x = angle #2
\n" ); document.write( " 10+ 2x = angle #3
\n" ); document.write( "x/2 = angle #4 (The fourth angle is half the measure of each of the equal angles)
\n" ); document.write( "x+x+10+2x+ x/2=360
\n" ); document.write( "(9/2)x = 350
\n" ); document.write( "x = 350(2/9)
\n" ); document.write( " \n" ); document.write( "

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