document.write( "Question 76851: A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of interest from both investments is $91. How much is invested at 8%. \n" ); document.write( "
Algebra.Com's Answer #55091 by funmath(2933)\"\" \"About 
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A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of interest from both investments is $91. How much is invested at 8%.
\n" ); document.write( "Let the amount invested at 10% be: x
\n" ); document.write( "Then the amount invested at 8% is: 2x
\n" ); document.write( "The formula for simple interest is: \"highlight%28I=Prt%29\" I=interest, P=amount invested(known also as Principal) r=interest rate and t=time in years
\n" ); document.write( "Since they didn't give you time, I assume it is one year and can be ignored.
\n" ); document.write( "rate=8/100=.08 for 8%
\n" ); document.write( "rate=10/100=.10 for 10%
\n" ); document.write( "I=91
\n" ); document.write( "Problem to solve:
\n" ); document.write( "\"91=.08%282x%29%2B.10%28x%29\"
\n" ); document.write( "\"91=.16x%2B.10x\"
\n" ); document.write( "\"91=.26x\"
\n" ); document.write( "\"91%2F.26=.26x%2F.26\"
\n" ); document.write( "\"350=x\"
\n" ); document.write( "The amount invested at 10% is: x=$350
\n" ); document.write( "The amount invested at 8% is 2x=2($350)=$700 <--that's what they asked for.
\n" ); document.write( "Happy Calculating!!!!
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