document.write( "Question 908255: Dan had two accounts he invested twice as much at 6% as he did at 5% if his annual interest is $68 how much did he invest in each \n" ); document.write( "

Algebra.Com's Answer #550897 by richwmiller(17219) $\"\"$ $\"About$

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We know that the interest for the two accounts is $68
\n" ); document.write( "0.06*x+0.05*y=68
\n" ); document.write( "We know that the account at 6% has 2 times the amount at 5%
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.06*(2*y)+0.05*y=68
\n" ); document.write( "We multiply out
\n" ); document.write( "(0.12+0.05)*y=68
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.17*y=68
\n" ); document.write( "Isolate y
\n" ); document.write( "y= 400.00
\n" ); document.write( "y=$ 400.00 at 5%
\n" ); document.write( "Calculate x
\n" ); document.write( "x=2*y
\n" ); document.write( "x=$ 800.00 at 6%
\n" ); document.write( "Your total for x is $ 800.00
\n" ); document.write( "Your total for y is $ 400.00
\n" ); document.write( "Your total for x and y is $ 1200.00
\n" ); document.write( "Total invested $ 800.00 + $ 400.00=$ 1200.00
\n" ); document.write( "We check
\n" ); document.write( "0.06* 800.00+0.05* 400.00=68
\n" ); document.write( " 48.00+ 20.00=68
\n" ); document.write( "68=68
\n" ); document.write( "Since this statement is TRUE and neither is negative then all is well.
\n" ); document.write( " \n" ); document.write( "

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