document.write( "Question 908207: One type of antifreeze is 40% glycol, and another type of antifreeze is 60% glycol. How much of each kind should be used to make 100 gallons of antifreeze that is 48% glycol? I know answer is 60 gallons of 40% and 40 gallons of 60% but need to see the equation and steps to solve to get these answers? Thank you! \n" ); document.write( "

Algebra.Com's Answer #550880 by dkppathak(439) $\"\"$ $\"About$

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One type of antifreeze is 40% glycol, and another type of antifreeze is 60% glycol. How much of each kind should be used to make 100 gallons of antifreeze that is 48% glycol?
\n" ); document.write( "let 40% glycole added is X gallon than pure glycole will be 40x/100=0.4X gallon
\n" ); document.write( "similarly let 60% glycol is Y gallon than pure glycol=60y/100=0.6Y gallon
\n" ); document.write( "pure glycol in 100 gallon should be 48% means pure glycol will be 48 gallon
\n" ); document.write( "as per given conditions
\n" ); document.write( "X+Y=100 (1)
\n" ); document.write( "0.4X+0.6Y =48(2) or 4x+6y=480 (2)
\n" ); document.write( "by multiplying (1) 4 and solving by elimination method
\n" ); document.write( "4X+4Y =400
\n" ); document.write( "4x+6y=480
\n" ); document.write( "Y=40 gallon
\n" ); document.write( "and X=60 gallon
\n" ); document.write( "Answer 60 gallon of 40% and 40 gallon of 60% glycol to be added for 48% glycol \n" ); document.write( "

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