document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908104>Question 908104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the solution in point-slope form of the the line perpendicular to 3x+2y=3y-7 and passing through (3,-2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550844 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the solution in point-slope form of the the line perpendicular to 3x+2y=3y-7 and passing through (3,-2)<BR>\n" );
document.write( "***<BR>\n" );
document.write( "3x+2y=3y-7<BR>\n" );
document.write( "y=3x+7<BR>\n" );
document.write( "slope,m=3<BR>\n" );
document.write( "slope of perpendicular line=-1/3(negative reciprocal)<BR>\n" );
document.write( "y-(-2)=(-1/3)(x-3)<BR>\n" );
document.write( "y+2=-(x-3)/3<BR>\n" );
document.write( "3y+6=-x+3<BR>\n" );
document.write( "x+3y=-3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );