document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908144>Question 908144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a cashier has 25 coins consisting of nickels dimes and quarters with a value of $4.90. <BR>\n" );
document.write( "If the number of dimes is 1 less than twice th number of nickels how many of each coin does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550843 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a cashier has 25 coins consisting of nickels dimes and quarters with a value of $4.90.If the number of dimes is 1 less than twice the number of nickels how many of each coin does she have?<BR>\n" );
document.write( "let x=number of nickels<BR>\n" );
document.write( "2x-1=number of dimes<BR>\n" );
document.write( "25-x-(2x-1)=25-x-2x+1=26-3x=number of quarters<BR>\n" );
document.write( ".05x+.10(2x-1)+.25(26-3x)=4.90<BR>\n" );
document.write( ".05x+.20x-.10+6.5-.75x=4.90<BR>\n" );
document.write( "-.50x=4.90+.10-6.5<BR>\n" );
document.write( ".50x=1.5<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "2x-1=5<BR>\n" );
document.write( "26-3x=17<BR>\n" );
document.write( "number of nickels=3<BR>\n" );
document.write( "number of dimes=5<BR>\n" );
document.write( "number of quarters=17 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );