document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908130>Question 908130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has a perimeter of 244 feet the width is 17 feet shorter than the length. find the length and width of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550821 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is a fence around.<BR>\n" );
document.write( "P = 2L + 2W<BR>\n" );
document.write( "W = L-17<BR>\n" );
document.write( "Take the known value of W from the second equation and put it into the first.<BR>\n" );
document.write( "P = 2L + 2W<BR>\n" );
document.write( "244 = 2L + 2(L-17)<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "244 = 2L + 2L -34<BR>\n" );
document.write( "Add 34 to each side<BR>\n" );
document.write( "278 = 4L<BR>\n" );
document.write( "Divide each side by 4<BR>\n" );
document.write( "L = 69.5<BR>\n" );
document.write( "If the length is 69.5, then the width is 52.5<BR>\n" );
document.write( "69.5 + 69.5 + 52.5 + 52.5 = 244 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );