document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908108>Question 908108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much pure acid should be mixed with 6 gallons of 50% acid solution in order to get an 80% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550815 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550815\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have 6 gal of 50% acid<BR>\n" );
document.write( "We want to add some 100% acid to make   80% acid<BR>\n" );
document.write( "1*x+0.5*6=0.8(6+x)<BR>\n" );
document.write( "1*x+3=4.8+0.8x<BR>\n" );
document.write( "1x-0.8x=4.8-3<BR>\n" );
document.write( "0.2x=1.8<BR>\n" );
document.write( "x=9 gal at 100% (9) is added to 6 gal at 50%(3) to make 80% of 15 gal(12)<BR>\n" );
document.write( "check<BR>\n" );
document.write( "1*9+0.5*6=0.8(6+9)<BR>\n" );
document.write( "9+3=0.8(15)<BR>\n" );
document.write( "12=12<BR>\n" );
document.write( "ok\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );