document.write( "Question 908096: How many quarts of pure antifreeze must be added to 11 quarts of a 25% antifreeze solution to obtain a 41% antifreeze solution \n" ); document.write( "
Algebra.Com's Answer #550813 by richwmiller(17219)\"\" \"About 
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We have 11 qt of 25% antifreeze
\n" ); document.write( "We want to add some 100% antifreeze to make 41% antifreeze
\n" ); document.write( "1*x+0.25*11=0.41(11+x)
\n" ); document.write( "1*x+2.75=4.51+0.41x
\n" ); document.write( "1x-0.41x=4.51-2.75
\n" ); document.write( "0.59x=1.76
\n" ); document.write( "x=2.98305085 qt at 100% (2.98305085) is added to 11 qt at 25%(2.75) to make 41% of 13.9830508 qt(5.73305085)
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\n" ); document.write( "1*2.98305085+0.25*11=0.41(11+2.98305085)
\n" ); document.write( "2.98305085+2.75=0.41(13.9830508)
\n" ); document.write( "5.73305085=5.73305085
\n" ); document.write( "ok
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