document.write( "Question 908100: A turboprop plane flying with the wind flew 960 mi in 3 h. Flying against the wind, the plane required 4 h to travel the same distance. Find the rate of the wind and the rate of the plane in calm air. \n" ); document.write( "
Algebra.Com's Answer #550810 by mananth(16946)\"\" \"About 
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plane speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 4 hours
\n" ); document.write( "with wind 3 hours
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\n" ); document.write( "Distance against 960 miles distance with 960 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "960.00 / ( x - y )= 4.00
\n" ); document.write( "4.00 ( x - y ) = 3.00
\n" ); document.write( "4.00 x - 4.00 y = 960.00 ....................1
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\n" ); document.write( "960.00 / ( x + y )= 3.00
\n" ); document.write( "3.00 ( x + y ) = 960.00
\n" ); document.write( "3.00 x + 3.00 y = 960.00 ...............2
\n" ); document.write( "Multiply (1) by 3.00
\n" ); document.write( "Multiply (2) by 4.00
\n" ); document.write( "we get
\n" ); document.write( "12.00 x + -12.00 y = 2880.00
\n" ); document.write( "12.00 x + 12.00 y = 3840.00
\n" ); document.write( "24.00 x = 6720.00
\n" ); document.write( "/ 24.00
\n" ); document.write( "x = 280.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "4.00 x -4.00 y = 960.00
\n" ); document.write( "1120.00 -4.00 -1120.00 = 960.00
\n" ); document.write( "-4.00 y = 960.00
\n" ); document.write( "-4.00 y = -160.00 mph
\n" ); document.write( " y = 40.00
\n" ); document.write( "plane speed 280.00 mph
\n" ); document.write( "wind speed 40.00 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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