document.write( "Question 908100: A turboprop plane flying with the wind flew 960 mi in 3 h. Flying against the wind, the plane required 4 h to travel the same distance. Find the rate of the wind and the rate of the plane in calm air. \n" ); document.write( "
Algebra.Com's Answer #550810 by mananth(16946)![]() ![]() You can put this solution on YOUR website! plane speed =x mph \n" ); document.write( "wind speed =y mph \n" ); document.write( "against wind 4 hours \n" ); document.write( "with wind 3 hours \n" ); document.write( " \n" ); document.write( "Distance against 960 miles distance with 960 miles \n" ); document.write( "t=d/r against wind - \n" ); document.write( "960.00 / ( x - y )= 4.00 \n" ); document.write( "4.00 ( x - y ) = 3.00 \n" ); document.write( "4.00 x - 4.00 y = 960.00 ....................1 \n" ); document.write( " \n" ); document.write( "960.00 / ( x + y )= 3.00 \n" ); document.write( "3.00 ( x + y ) = 960.00 \n" ); document.write( "3.00 x + 3.00 y = 960.00 ...............2 \n" ); document.write( "Multiply (1) by 3.00 \n" ); document.write( "Multiply (2) by 4.00 \n" ); document.write( "we get \n" ); document.write( "12.00 x + -12.00 y = 2880.00 \n" ); document.write( "12.00 x + 12.00 y = 3840.00 \n" ); document.write( "24.00 x = 6720.00 \n" ); document.write( "/ 24.00 \n" ); document.write( "x = 280.00 mph \n" ); document.write( " \n" ); document.write( "plug value of x in (1) y \n" ); document.write( "4.00 x -4.00 y = 960.00 \n" ); document.write( "1120.00 -4.00 -1120.00 = 960.00 \n" ); document.write( "-4.00 y = 960.00 \n" ); document.write( "-4.00 y = -160.00 mph \n" ); document.write( " y = 40.00 \n" ); document.write( "plane speed 280.00 mph \n" ); document.write( "wind speed 40.00 mph \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |