document.write( "Question 76831: When I divided the product of 3 consecutive positive integers by their mean, I got 99. What is the smallest of the three numbers? \n" ); document.write( "
Algebra.Com's Answer #55080 by checkley75(3666)\"\" \"About 
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WHEN YOU HAVE THREE CONSECUTIVE NUMBERS SAY 5,6 & 7 THE MEAN OR AVERAGE IS ALWAYS THE MIDDLE NUMBER (5*6*7)/6=210/6=35
\n" ); document.write( "BECAUSE WE'VE ELIMINATED THE MIDDLE NUMBER WE HAVE LEFT
\n" ); document.write( "X(X+2)=35
\n" ); document.write( "X^2+2X-35=0
\n" ); document.write( "(X-5)(X+7)=0
\n" ); document.write( "X-5=0
\n" ); document.write( "X=5 ANSWER
\n" ); document.write( "X+2=7 ANSWER
\n" ); document.write( "--------------------------------------------
\n" ); document.write( "[X*(X+1)*(X+2)]/(X+1)=99
\n" ); document.write( "X(X+2)=99
\n" ); document.write( "X^2+2X-99=0
\n" ); document.write( "(X-9)(X+11)=0
\n" ); document.write( "X-9=0
\n" ); document.write( "X=9 ANSWER. THE OTHER TWO NUMBERS ARE 9+1=10 & 9+2=11
\n" ); document.write( "PROOF
\n" ); document.write( "(9*10*11)/10=99
\n" ); document.write( "(9*11)=99
\n" ); document.write( "99=99 \n" ); document.write( "
\n" );