document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=908082>Question 908082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of a metal containing 80% Nicole must be combined with 3 pounds of a metal containing 20% Nicole to form an alloy containing 62% nickel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550787 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have 3 lb of 20% alloy<BR>\n" );
document.write( "We want to add some 80% alloy to make   62% alloy<BR>\n" );
document.write( "0.8*x+0.2*3=0.62(3+x)<BR>\n" );
document.write( "0.8*x+0.6=1.86+0.62x<BR>\n" );
document.write( "0.8x-0.62x=1.86-0.6<BR>\n" );
document.write( "0.18x=1.26<BR>\n" );
document.write( "x=7 lb at 80% (5.6) is added to 3 lb at 20%(0.6) to make 62% of 10 lb(6.2)<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.8*7+0.2*3=0.62(3+7)<BR>\n" );
document.write( "5.6+0.6=0.62(10)<BR>\n" );
document.write( "6.2=6.2<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );