document.write( "Question 908036: An investment of $2000 is made at an annual simple interest rate of 5.5%. How much additional money must be invested at an annual simple interest rate of 7% so that the total interest earned is 6% of the total investment? \n" ); document.write( "
Algebra.Com's Answer #550767 by richwmiller(17219)\"\" \"About 
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one investment all 3 rates
\n" ); document.write( "0.055*2000+0.07(x)=0.06(2000+x)
\n" ); document.write( "Multiply out.
\n" ); document.write( "110.0+0.07(x)=120+0.06x
\n" ); document.write( "combine like terms
\n" ); document.write( "0.01x=10.0
\n" ); document.write( "isolate x
\n" ); document.write( "x=10.0/0.01
\n" ); document.write( "Divide
\n" ); document.write( "x=1000.0
\n" ); document.write( "check
\n" ); document.write( "0.055*2000+0.07(x)=0.06(2000+x)
\n" ); document.write( "110.0+0.07*1000=0.06(2000+1000)
\n" ); document.write( "110.0+70=0.06(3000)
\n" ); document.write( "180.0=180
\n" ); document.write( "ok
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