document.write( "Question 908036: An investment of $2000 is made at an annual simple interest rate of 5.5%. How much additional money must be invested at an annual simple interest rate of 7% so that the total interest earned is 6% of the total investment? \n" ); document.write( "
Algebra.Com's Answer #550767 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! one investment all 3 rates \n" ); document.write( "0.055*2000+0.07(x)=0.06(2000+x) \n" ); document.write( "Multiply out. \n" ); document.write( "110.0+0.07(x)=120+0.06x \n" ); document.write( "combine like terms \n" ); document.write( "0.01x=10.0 \n" ); document.write( "isolate x \n" ); document.write( "x=10.0/0.01 \n" ); document.write( "Divide \n" ); document.write( "x=1000.0 \n" ); document.write( "check \n" ); document.write( "0.055*2000+0.07(x)=0.06(2000+x) \n" ); document.write( "110.0+0.07*1000=0.06(2000+1000) \n" ); document.write( "110.0+70=0.06(3000) \n" ); document.write( "180.0=180 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |