document.write( "Question 908039: On two investments totaling $8,000, Lydia lost 4% on one and earned 6% on the other. If her net annual receipts were $400, how much was each investment? \n" ); document.write( "
Algebra.Com's Answer #550760 by richwmiller(17219)\"\" \"About 
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Total amount of money invested: $8000
\n" ); document.write( "x+y=8000,
\n" ); document.write( "Total yearly interest for the two accounts is: $400
\n" ); document.write( "-0.04*x+0.06*y=400
\n" ); document.write( "x=8000-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "-0.04*(8000-y)+0.06*y=400
\n" ); document.write( "Multiply out
\n" ); document.write( "-320--0.04y+0.06*y=400
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.1*y=720
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$ 7200.00 at 6%
\n" ); document.write( "x=8000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$ 800.00 at -4% at a loss
\n" ); document.write( "Check
\n" ); document.write( "-0.04*800+0.06*7200=400
\n" ); document.write( "-32+432=400
\n" ); document.write( "400=400
\n" ); document.write( "If this statement is TRUE and neither x nor y is negative then all is well
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