document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907910>Question 907910</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The probability that a part produced by a certain factory's assembly line will be defective is 0.026. Find the probabilities that in a run of 42 items, the following results ware obtained:\r<BR>\n" );
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document.write( "A. The probabilty that exacly 3 parts will be defective is:\r<BR>\n" );
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document.write( "B. The probabilty that no more than 2 parts will be defective is:\r<BR>\n" );
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document.write( "C. The probability that at least 1 part will be defective is: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550713 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p(def) = .026 , n = 42<BR>\n" );
document.write( "P(x=3) = binompdf(42, .026, 3)<BR>\n" );
document.write( "P(x > 2) = 1 - P(x&#8804;1) = 1 - binomcdf(42, .026, 1)<BR>\n" );
document.write( "P(at least one) = 1 - P(none) = 1 - binompdf(42, .026, 0)  </SPAN>\n" );
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