document.write( "Question 76775: Business and finance. Kevin earned $165 interest for 1 year on an investment of
\n" );
document.write( "$1500. At the same rate, what amount of interest would be earned by an investment of $2500? \n" );
document.write( "
Algebra.Com's Answer #55068 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 165/1500=X/2500 CROSS MULTIPLYING WE GET: \n" ); document.write( "1500X=165*2500 \n" ); document.write( "1500X=412500 \n" ); document.write( "X=412500/1500 \n" ); document.write( "X=$275 IS THE INTEREST ON AN INVESTMENT OF $2500. \n" ); document.write( "BASED ON AN INTEREST RATE OF 11% (165/1500=.11=11%). \n" ); document.write( " |