document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=76799>Question 76799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Will someone show me the steps to solve this problems so that I will be able to work othere like this or similar to it.\r<BR>\n" );
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document.write( "The shorter leg of a right triangle is 11 meters. The hypotenuse is 1 meter longer than the longer leg. Find the length of the longer leg. <BR>\n" );
document.write( "Thank you,<BR>\n" );
document.write( "Sabrina  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55067 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the problem is about a right triangle, think about using the Pythagorean theorem: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2+%2B+b%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2+%2B+b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Where: c is the length of the hypotenuse and a & b are the lengths of the two legs.<BR>\n" );
document.write( "In this problem, you are given the length of one of the legs (11 m.) and you are told that the length of the hypotenuse is 1 meter longer than the other (longer) leg.<BR>\n" );
document.write( "So, we'll let x meters be the length of the longer leg.<BR>\n" );
document.write( "Then the length of the hypotenuse will be x+1 meters.<BR>\n" );
document.write( "Now let's apply the Pythagorean theorem.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B1%29%5E2+=+11%5E2+%2B+x%5E2 ALIGN=MIDDLE  ALT=\"%28x%2B1%29%5E2+=+11%5E2+%2B+x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify this.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B2x%2B1+=+121+%2B+x%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2B2x%2B1+=+121+%2B+x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2 ALIGN=MIDDLE  ALT=\"x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > from both sides of the equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B1+=+121 ALIGN=MIDDLE  ALT=\"2x%2B1+=+121\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now subtract 1 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+=+120 ALIGN=MIDDLE  ALT=\"2x+=+120\"   DISABLED_style= \"max-width:90%; height:auto;\" > Finally, divide both sides by 2.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+60 ALIGN=MIDDLE  ALT=\"x+=+60\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The length of the longer leg is 60 meters. </SPAN>\n" );
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