document.write( "Question 907620: If i invested 10,000 between two stocks, after a year returns were 6% and 5.75%, and total return received was 588.75, how much did i invest in each stock? \n" ); document.write( "

Algebra.Com's Answer #550638 by richwmiller(17219) $\"\"$ $\"About$

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Total amount of money invested: $10000
\n" ); document.write( "x+y=10000,
\n" ); document.write( "Total yearly interest for the two accounts is: $588.75
\n" ); document.write( "0.06*x+0.0575*y=588.75
\n" ); document.write( "x=10000-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.06*(10000-y)+0.0575*y=588.75
\n" ); document.write( "Multiply out
\n" ); document.write( "600-0.06y+0.0575*y=588.75
\n" ); document.write( "Combine like terms.
\n" ); document.write( "-0.0025*y=-11.25
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$ 4500.00 at 5.75%
\n" ); document.write( "x=10000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$ 5500.00 at 6%
\n" ); document.write( "Check
\n" ); document.write( "0.06*5500+0.0575*4500=588.75
\n" ); document.write( "330+258.75=588.75
\n" ); document.write( "588.75=588.75
\n" ); document.write( "If this statement is TRUE and neither x nor y is negative then all is well
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