document.write( "Question 76810: Please help.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 2 ft longer than the width. If the area is 16 ft^2, then what are the length and width?
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Algebra.Com's Answer #55062 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
x(x+2)=16
\n" ); document.write( "x^2+2x-16=0
\n" ); document.write( "using the quadratic equation we get:
\n" ); document.write( "X=(-2+-SQRT[2^2-4*1*-16])/2*1
\n" ); document.write( "X=(-2+-SQRT[4+64])/2
\n" ); document.write( "X=(-2+-SQRT68)/2
\n" ); document.write( "X=(-2+-8.246)/2
\n" ); document.write( "X=(-2+8.246)/2
\n" ); document.write( "X=6.246/2
\n" ); document.write( "X=3.123 ANSWER FOR THE SHORT SIDE.
\n" ); document.write( "3.123+2=5.123 ANSWER FOR THE LONG SIDE.
\n" ); document.write( "PROOF
\n" ); document.write( "3.123*5.123=16
\n" ); document.write( "16=16\r
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