document.write( "Question 76810: Please help.\r
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document.write( "The length of a rectangle is 2 ft longer than the width. If the area is 16 ft^2, then what are the length and width? \n" );
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Algebra.Com's Answer #55062 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! x(x+2)=16 \n" ); document.write( "x^2+2x-16=0 \n" ); document.write( "using the quadratic equation we get: \n" ); document.write( "X=(-2+-SQRT[2^2-4*1*-16])/2*1 \n" ); document.write( "X=(-2+-SQRT[4+64])/2 \n" ); document.write( "X=(-2+-SQRT68)/2 \n" ); document.write( "X=(-2+-8.246)/2 \n" ); document.write( "X=(-2+8.246)/2 \n" ); document.write( "X=6.246/2 \n" ); document.write( "X=3.123 ANSWER FOR THE SHORT SIDE. \n" ); document.write( "3.123+2=5.123 ANSWER FOR THE LONG SIDE. \n" ); document.write( "PROOF \n" ); document.write( "3.123*5.123=16 \n" ); document.write( "16=16\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |