document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907778>Question 907778</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a line described as follows and express your answer in point-slope form, slope-intercept form, and standard form<BR>\n" );
document.write( "Find the equation of the line perpendicular to the line y+3=3(x-5) that passes through the point (1, -4)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550591 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> slope of perpendicular line  m = (-1/3)  Negative reciprocal of m = 3 <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%2F3%293+=+-1 ALIGN=MIDDLE  ALT=\"%28-1%2F3%293+=+-1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "y+4 = (-1/3)(x-1) point-slope form <BR>\n" );
document.write( "y =(-1/3)x  - 11/3 slope-intercept form<BR>\n" );
document.write( "x + 3y = -11 standard form </SPAN>\n" );
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