document.write( "Question 907629: The width of a rectangle is 12 feet less than the length. The area of the rectangle is 540 square feet. Find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #550562 by Fombitz(32388) $\"\"$ $\"About$

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For a rectangle,
\n" ); document.write( " $\"A=L%2AW\"$
\n" ); document.write( " $\"540=L%2A%28L-12%29\"$
\n" ); document.write( " $\"540=L%5E2-12L\"$
\n" ); document.write( " $\"L%5E2-12L-540=0\"$
\n" ); document.write( " $\"%28L%2B18%29%28L-30%29=0\"$
\n" ); document.write( "Two solutions but only one is positive.
\n" ); document.write( " $\"L-30=0\"$
\n" ); document.write( " $\"L=30\"$
\n" ); document.write( "Then,
\n" ); document.write( " $\"W=30-12\"$
\n" ); document.write( " $\"W=18\"$
\n" ); document.write( " \n" ); document.write( "

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