document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907744>Question 907744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angle A and Angle B form a linear pair. Fifty one less than the measure of angle B is equal to twice the measure of angle A. What is the measure OF THE COMPLEMENT OF ANGLE A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550537 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A and B form a linear pair.<BR>\n" );
document.write( "this means A + B = 180\r<BR>\n" );
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document.write( "fifty one less than the measure of B is equal to 2 * the measure of A.<BR>\n" );
document.write( "this means B - 51 = 2 * A\r<BR>\n" );
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document.write( "you want to find the complement of A.<BR>\n" );
document.write( "this means you want to find 90 - A.\r<BR>\n" );
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document.write( "you have 2 equations that need to be solved simultaneously to get a solution that is common to both of them.\r<BR>\n" );
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document.write( "the equations are:\r<BR>\n" );
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document.write( "A + B = 180 (first equation)<BR>\n" );
document.write( "B - 51 = 2 * A (second equation)\r<BR>\n" );
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document.write( "solve for  A in the first equation to get A = 180 - B\r<BR>\n" );
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document.write( "replace A with 180 - B in the second equation to get B - 51 = = 2 * (180 - B)\r<BR>\n" );
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document.write( "this allows you to solve for B in the second equation.\r<BR>\n" );
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document.write( "simplify to get B - 51 = 2 * 180 - 2 * B\r<BR>\n" );
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document.write( "simplify further to get B - 51 = 360 - 2 * B\r<BR>\n" );
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document.write( "add 2 * B to both equations to get 3 * B - 51 = 360\r<BR>\n" );
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document.write( "add 51 to both sides of the equation to get 3 * B = 411\r<BR>\n" );
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document.write( "divide both sides of the equation by 3 to get B = 137\r<BR>\n" );
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document.write( "replace B in the first equation with 137 to get A + 137 = 180\r<BR>\n" );
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document.write( "subtract 137 from both sides of the equation to get A = 43\r<BR>\n" );
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document.write( "you want to find the complement of A so you want to find 90 - A.\r<BR>\n" );
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document.write( "replace A in that equation with 43 to get complement of A = 90 - 43 which makes the complement of A = 47 degrees.\r<BR>\n" );
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document.write( "that's your solution.\r<BR>\n" );
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document.write( "you can go back to your original equations to confirm the solution is correct.\r<BR>\n" );
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document.write( "if the complement of A is 47, this means that A is 43.\r<BR>\n" );
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document.write( "you already solved for B to get B = 137.\r<BR>\n" );
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document.write( "A + B = 180 becomes 43 + 137 = 180 which becomes 180 = 180.<BR>\n" );
document.write( "this confirms that A and B are correct.\r<BR>\n" );
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document.write( "fifty one less than B is equal to twice A becomes 137 - 51 = 2*43 which becomes 86 = 86.<BR>\n" );
document.write( "this confirms that fifty one less than B is equal to twice A.\r<BR>\n" );
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document.write( "the solution of A = 43 and B = 137 is correct.\r<BR>\n" );
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document.write( "the complement of A is equal to 9 - 43 which is equal to 47 which is the solution you were asked to find.<BR>\n" );
document.write( " </SPAN>\n" );
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