document.write( "Question 907728: Elizabeth Suco and her friend Harold Tanner are riding their bicycles in a fundraiser for charity. Harold leaves the starting point at 7:00 AM and rides at 15 miles per hour. Elizabeth leaves the starting point at 7:30 AM and rides at 18 miles per hour.
\n" ); document.write( "How long after Elizabeth leaves the starting point will she catch up?
\n" ); document.write( "How far from the starting point will they be? \n" ); document.write( "
Algebra.Com's Answer #550519 by lwsshak3(11628)\"\" \"About 
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Elizabeth Suco and her friend Harold Tanner are riding their bicycles in a fundraiser for charity. Harold leaves the starting point at 7:00 AM and rides at 15 miles per hour. Elizabeth leaves the starting point at 7:30 AM and rides at 18 miles per hour.How long after Elizabeth leaves the starting point will she catch up? How far from the starting point will they be?
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\n" ); document.write( "let x=Elizabeth's travel time
\n" ); document.write( "x+.5=Harolds's travel time
\n" ); document.write( "speed*travel time=distance (equal for both)
\n" ); document.write( "..
\n" ); document.write( "15(x+.5)=18x
\n" ); document.write( "15x+7.5=18x
\n" ); document.write( "3x=7.5
\n" ); document.write( "x=2.5
\n" ); document.write( "18x=45
\n" ); document.write( "How long after Elizabeth leaves the starting point will she catch up? 2.5 hrs
\n" ); document.write( "How far from the starting point will they be? 45 miles \n" ); document.write( "
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