document.write( "Question 907695: Eighty one percent of U.S. households have DVD players. Choose 6 households at random. What is the probability that at least one does not have a DVD player? \n" ); document.write( "
Algebra.Com's Answer #550498 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Eighty one percent of U.S. households have DVD players. Choose 6 households at random. What is the probability that at least one does not have a DVD player? \n" ); document.write( "---------------- \n" ); document.write( "P(at least one does not have) = 1 - P(all have a DVD player) \n" ); document.write( "-------------- \n" ); document.write( "P(at least one) = 1 - (0.81)^6 = 1 - 0.7176 = 0.2824 \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |