document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907669>Question 907669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much quantity each of pure tin and iron must be added to 600 kilograms of an alloy containing 20% tin and 40% iron to make an alloy which is 25% tin and 50% iron? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550489 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .20*600=600/5=120 kilos of tin  we want .25 or 1/4 or 25% <BR>\n" );
document.write( ".40*600=240 kilos of iron we want 50% or .5 or 1/2\r<BR>\n" );
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document.write( "(1) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28+a+%2B+120+%29+%2F+%28+a+%2B+b+%2B+600+%29+=+.25+ ALIGN=MIDDLE  ALT=\"+%28+a+%2B+120+%29+%2F+%28+a+%2B+b+%2B+600+%29+=+.25+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "(2) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28+b+%2B+240+%29+%2F+%28+a+%2B+b+%2B+600+%29+=+.50+ ALIGN=MIDDLE  ALT=\"+%28+b+%2B+240+%29+%2F+%28+a+%2B+b+%2B+600+%29+=+.50+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "(a + 120 ) / ( a + b + 600 ) = .25,<BR>\n" );
document.write( "( b + 240 ) / ( a + b + 600 ) = .50 <BR>\n" );
document.write( "a=120 tin<BR>\n" );
document.write( "b=240 iron<BR>\n" );
document.write( "240/960=1/4<BR>\n" );
document.write( "480/960=1/2 </SPAN>\n" );
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