document.write( "Question 907625: A total of $6000 is invested: part at 9% and the remainder at 14%. How much is invested at each rate if the annual interest is $740? \n" ); document.write( "

Algebra.Com's Answer #550483 by mananth(16946) $\"\"$ $\"About$

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Part I 9.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 14.00% per annum ------------ Amount invested = y
\n" ); document.write( " 6000
\n" ); document.write( "Interest----- 740.00
\n" ); document.write( "
\n" ); document.write( "Part I 9.00% per annum ---x
\n" ); document.write( "Part II 14.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 6000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "9.00% x + 14.00% y= 740
\n" ); document.write( "Multiply by 100
\n" ); document.write( "9 x + 14 y= 74000.00 --------2
\n" ); document.write( "Multiply (1) by -9
\n" ); document.write( "we get
\n" ); document.write( "-9 x -9 y= -54000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 5 y= 20000
\n" ); document.write( "divide by 5
\n" ); document.write( " y = 4000
\n" ); document.write( "Part I 9.00% $ 2000
\n" ); document.write( "Part II 14.00% $ 4000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "2000 --------- 9.00% ------- 180.00
\n" ); document.write( "4000 ------------- 14.00% ------- 560.00
\n" ); document.write( "Total -------------------- 740.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

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