document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907512>Question 907512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the equation is ax-x=c<BR>\n" );
document.write( "and i saw the problem was solved and the number 1 was in the solution but i don't understand where the 1 came from. can you please explain in really simple steps  ?  What i got was x=c+x/a </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550414 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You want to solve for x in terms of other variables (excluding x). So while your answer x = (c+x)/a is algebraically correct, it isn't completely in terms of other variables.\r<BR>\n" );
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document.write( "Factor the LHS to x(a-1) = c, divide both sides by a-1 to get x = c/(a-1). </SPAN>\n" );
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