In order to factor , first we need to ask ourselves: What two numbers multiply to -45 and add to 4? Lets find out by listing all of the possible factors of -45 \n" );
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document.write( " Factors: \n" );
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document.write( " 1,3,5,9,15,45, \n" );
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document.write( " -1,-3,-5,-9,-15,-45,List the negative factors as well. This will allow us to find all possible combinations \n" );
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document.write( " These factors pair up to multiply to -45. \n" );
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document.write( " (-1)*(45)=-45 \n" );
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document.write( " (-3)*(15)=-45 \n" );
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document.write( " (-5)*(9)=-45 \n" );
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document.write( " Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4 \n" );
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document.write( " First Number | | | Second Number | | | Sum | 1 | | | -45 | || | 1+(-45)=-44 | 3 | | | -15 | || | 3+(-15)=-12 | 5 | | | -9 | || | 5+(-9)=-4 | -1 | | | 45 | || | (-1)+45=44 | -3 | | | 15 | || | (-3)+15=12 | -5 | | | 9 | || | (-5)+9=4 | We can see from the table that -5 and 9 add to 4.So the two numbers that multiply to -45 and add to 4 are: -5 and 9\r\n" );
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document.write( " Now we substitute these numbers into a and b of the general equation of a product of linear factors which is:\r\n" );
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document.write( " substitute a=-5 and b=9\r\n" );
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document.write( " So the equation becomes:\r\n" );
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document.write( " (x-5)(x+9)\r\n" );
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document.write( " Notice that if we foil (x-5)(x+9) we get the quadratic again\n" );
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document.write( "If we replace the x's with a's we get\r \n" );
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document.write( "So factors to \n" );
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