document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907271>Question 907271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorboat maintained a constant speed of 12 miles per hour relative to the water in going 45 miles upstream and then returning. the total time for the trip was 8.0 hours. Use this information to find the speed of the current </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550397 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r*t=d<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "d/r+d/r=t<BR>\n" );
document.write( "45/(12-c)+45/(12+c)=8<BR>\n" );
document.write( "(12-c)*(12+c)=(144-c^2)<BR>\n" );
document.write( "45*(12+c)/(144-c^2))+45*(12-c)/(144-c^2)=8<BR>\n" );
document.write( "(540+45*c)+540-45*c))/(144-c^2)=8<BR>\n" );
document.write( "(540+540)/(144-c^2)=8<BR>\n" );
document.write( "(1080)/(144-c^2)=8<BR>\n" );
document.write( "1080=8*(144-c^2)<BR>\n" );
document.write( "135=144-c^2<BR>\n" );
document.write( "135-144=-c^2<BR>\n" );
document.write( "-9=-c^2<BR>\n" );
document.write( "c^2=9<BR>\n" );
document.write( "c=+-3.0<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );