document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907423>Question 907423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using the intermediate value theorem, determine whether the function has at least one real zero between a and b. \r<BR>\n" );
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document.write( "    a. f(x) = x 3 + 3x 2 – 9x – 13       a = - 5    b = - 4\r<BR>\n" );
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document.write( "    b. f(x) = 3x 2 – 2x – 11      a = - 3     b = - 2\r<BR>\n" );
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document.write( "Thank you for the help in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550335 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = x^3 + 3x^2 – 9x – 13  |Note use of ^ (uppercase 6)<BR>\n" );
document.write( "f(-5) = -18<BR>\n" );
document.write( "f(-4) = 7   <BR>\n" );
document.write( "Negative to positive<BR>\n" );
document.write( "Obviously curve crosses x-axis (has at least one real zero ) between -5 and -4.<BR>\n" );
document.write( "Graphing Calculator a must<BR>\n" );
document.write( "If not...<BR>\n" );
document.write( "dl the FREE graph software at<BR>\n" );
document.write( "http://www.padowan.dk.com </SPAN>\n" );
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