document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907402>Question 907402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trying to solve by substitution but I can seem to get it right. <BR>\n" );
document.write( "18x-6y=-12<BR>\n" );
document.write( "y=-3x-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550328 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 18x-6y=-12<BR>\n" );
document.write( "18x-6(-3x+2)=-12<BR>\n" );
document.write( "18x + 18x - 12 = -12<BR>\n" );
document.write( "36x = 0<BR>\n" );
document.write( "x = 0  and y = 2 <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+18%2A0+-6y+=+-12 ALIGN=MIDDLE  ALT=\"+18%2A0+-6y+=+-12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Ordered Pair (0,2) the Solution for this System of EQs<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );