document.write( "Question 907385: How many liters of a 60% acid solution must be mixed with a 25% acid solution to get 315L of a 50% acid solution? \n" ); document.write( "
Algebra.Com's Answer #550319 by ewatrrr(24785)\"\" \"About 
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x 60% amount
\n" ); document.write( ".60x + .25(315L - x) = .50(315L)
\n" ); document.write( "x = .25(315L)/.35
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