document.write( "Question 907385: How many liters of a 60% acid solution must be mixed with a 25% acid solution to get 315L of a 50% acid solution? \n" ); document.write( "
Algebra.Com's Answer #550319 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! x 60% amount \n" ); document.write( ".60x + .25(315L - x) = .50(315L) \n" ); document.write( "x = .25(315L)/.35 \n" ); document.write( " |