document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907353>Question 907353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bert can clean the sidewalks around the building in 2 hours in using a blower. Dennis can do the same job in 8 hours in using a broom. How long would it take them working together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550309 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/a+1/b=1/x<BR>\n" );
document.write( "1/2+1/8=1/x<BR>\n" );
document.write( "8/16+2/16=1/x<BR>\n" );
document.write( "10/16=1/x<BR>\n" );
document.write( "x=16/10<BR>\n" );
document.write( "x=1.6 hours working together<BR>\n" );
document.write( "check<BR>\n" );
document.write( "x/a+c/b=1<BR>\n" );
document.write( "1.6/2+1.6/8=1<BR>\n" );
document.write( ".8+.2=1<BR>\n" );
document.write( "1=1<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );