document.write( "Question 907325: Mary is 15 years older than her sister Jane. Six years ago Mary was 6 times as old as Jane.What is the sum of their ages? \n" ); document.write( "
Algebra.Com's Answer #550241 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
M = J + 15
\n" ); document.write( "M-6 = 6(J-6)
\n" ); document.write( "Distribute
\n" ); document.write( "M-6 = 6J-36
\n" ); document.write( "Add 6 to each side
\n" ); document.write( "M = 6J-30
\n" ); document.write( "Take the value of M from the top equation and substitute it in the bottom.
\n" ); document.write( "M = 6J - 30
\n" ); document.write( "(J+15) = 6J-30
\n" ); document.write( "Subtract J from each side
\n" ); document.write( "15 = 5J - 30
\n" ); document.write( "Add 30 to each side
\n" ); document.write( "45 = 5J
\n" ); document.write( "Divide each side by 5
\n" ); document.write( "9 = J
\n" ); document.write( "If Jane is 9, then Mary is 24

\n" ); document.write( "6 years ago, Jane was 3. 6 years ago, Mary was 18, which is 6 * 3.
\n" ); document.write( "
\n" ); document.write( "
\n" );