document.write( "Question 907325: Mary is 15 years older than her sister Jane. Six years ago Mary was 6 times as old as Jane.What is the sum of their ages? \n" ); document.write( "
Algebra.Com's Answer #550241 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! M = J + 15 \n" ); document.write( "M-6 = 6(J-6) \n" ); document.write( "Distribute \n" ); document.write( "M-6 = 6J-36 \n" ); document.write( "Add 6 to each side \n" ); document.write( "M = 6J-30 \n" ); document.write( "Take the value of M from the top equation and substitute it in the bottom. \n" ); document.write( "M = 6J - 30 \n" ); document.write( "(J+15) = 6J-30 \n" ); document.write( "Subtract J from each side \n" ); document.write( "15 = 5J - 30 \n" ); document.write( "Add 30 to each side \n" ); document.write( "45 = 5J \n" ); document.write( "Divide each side by 5 \n" ); document.write( "9 = J \n" ); document.write( "If Jane is 9, then Mary is 24 \n" ); document.write( "6 years ago, Jane was 3. 6 years ago, Mary was 18, which is 6 * 3. \n" ); document.write( " \n" ); document.write( " |