document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907253>Question 907253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A long distance runner starts at the beginning of a trail and runs at a rate of <BR>\n" );
document.write( "4 miles per hour. Three hours later, a cyclist starts at the beginning of the trail and travels at a rate of <BR>\n" );
document.write( "19 miles per hour. What is the amount of time that the cyclist travels before overtaking the runner?<BR>\n" );
document.write( "Do not do any rounding. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550224 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I walk 4 mph!!<BR>\n" );
document.write( "Gaining speed 19 -4= 15 mph<BR>\n" );
document.write( "Headstart 4*3 =12 miles<BR>\n" );
document.write( "Time to catch up 12/15=0.8 hours<BR>\n" );
document.write( "Time to catch up =48 minutes<BR>\n" );
document.write( "Algebraic solution<BR>\n" );
document.write( "4(t+3)=19t<BR>\n" );
document.write( "4t+12=19t<BR>\n" );
document.write( "12=19t-4t<BR>\n" );
document.write( "12=15t<BR>\n" );
document.write( "t=0.8  hours<BR>\n" );
document.write( "Distance to meeting 0.8*19=15.2 miles\r<BR>\n" );
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