document.write( "Question 907288: An investor divided $4,000 into two unequal parts. One of them was invested at 5.5% annual simple interest, and the other at 6.7%.
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document.write( "After 1 year, the interest on both investments was $253.\r
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document.write( "Find how much money was invested at 5.5%.
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Algebra.Com's Answer #550219 by richwmiller(17219) You can put this solution on YOUR website! Total amount of money invested: $4000 \n" ); document.write( "x+y=4000, \n" ); document.write( "Total yearly interest for the two accounts is: $253 \n" ); document.write( "0.055*x+0.067*y=253 \n" ); document.write( "x=4000-y \n" ); document.write( "Substitute for x \n" ); document.write( "0.055*(4000-y)+0.067*y=253 \n" ); document.write( "Multiply out \n" ); document.write( "220.0-0.055y+0.067*y=253 \n" ); document.write( "Combine like terms. \n" ); document.write( "0.012*y=33.0 \n" ); document.write( "Isolate y \n" ); document.write( "y=$ 2750.00 at 6.7% \n" ); document.write( "x=4000-y \n" ); document.write( "Calculate x \n" ); document.write( "x=$ 1250.00 at 5.5% \n" ); document.write( "Check \n" ); document.write( "0.055*1250.0+0.067*2750.0=253 \n" ); document.write( "68.75+184.25=253 \n" ); document.write( "253.0=253 \n" ); document.write( "If this statement is TRUE and neither x nor y is negative then all is well \n" ); document.write( " \n" ); document.write( " |