document.write( "Question 76730: Martha can rake the leaves in her yard in 5 hours. Her younger brother can do the job in 6 hours How long will it take if they work together? \n" ); document.write( "
Algebra.Com's Answer #55019 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Martha can rake the leaves in her yard in 5 hours. \r\n" ); document.write( "Her younger brother can do the job in 6 hours \r\n" ); document.write( "How long will it take if they work together?\r\n" ); document.write( "\r\n" ); document.write( "Martha can rake the leaves in her yard in 5 hours.\r\n" ); document.write( "So in ONE hour, she can rake 1/5th of the leaves.\r\n" ); document.write( "Therefore in x hours, she can rake x/5ths of the leaves.\r\n" ); document.write( "\r\n" ); document.write( "Her younger brother can do the job in 6 hours\r\n" ); document.write( "So in ONE hour, he can rake 1/6th of the leaves.\r\n" ); document.write( "Therefore in x hours, he can rake x/6ths of the leaves.\r\n" ); document.write( "\r\n" ); document.write( "The fraction of the leaves Martha rakes +\r\n" ); document.write( " The fraction of the leaves her younger brother rakes =\r\n" ); document.write( " 1 yardful of leaves\r\n" ); document.write( "\r\n" ); document.write( " x/5 + x/6 = 1\r\n" ); document.write( "\r\n" ); document.write( "Multiply through by LCD, which is 30\r\n" ); document.write( "\r\n" ); document.write( " 30(x/5)+ 30(x/6) = 30(1)\r\n" ); document.write( "\r\n" ); document.write( " 6x + 5x = 30\r\n" ); document.write( "\r\n" ); document.write( " 11x = 30\r\n" ); document.write( "\r\n" ); document.write( " x = 30/11 \r\n" ); document.write( "\r\n" ); document.write( " x = 2 8/11\r\n" ); document.write( "\r\n" ); document.write( " x = 2 hr, 43 mins, 38 2/11 sec.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |