document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907018>Question 907018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving problems like\r<BR>\n" );
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document.write( "A nurse wishes to add 30 ounces of a 10% solution of benzalkonium Chloride to dilute a 4% solution. How much water should she add? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550153 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have 30 oz of 10% solution<BR>\n" );
document.write( "We want to add some 0% solution  to make   4% solution<BR>\n" );
document.write( "0*x+0.1*30=0.04(30+x)<BR>\n" );
document.write( "0*x+3=1.2+0.04x<BR>\n" );
document.write( "0x-0.04x=1.2-3<BR>\n" );
document.write( "-0.04x=-1.8<BR>\n" );
document.write( "x=45 oz of 0% (0) is added to 30 oz at 10%(3) to make 4% of 75 oz(3)<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0*45+0.1*30=0.04(30+45)<BR>\n" );
document.write( "0+3=0.04(75)<BR>\n" );
document.write( "3=3<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
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