document.write( "Question 906940: How many gallons of water that is 74% alcohol must be mixed with 5 gallons of one that is 90% alcohol in order to obtain a mixture that is 84% alcohol? \n" ); document.write( "
Algebra.Com's Answer #550108 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! We have 5 gal of 90% solution \n" ); document.write( "We want to add some 74% solution to make 84% solution \n" ); document.write( "0.74*x+0.9*5=0.84(5+x) \n" ); document.write( "0.74*x+4.5=4.2+0.84x \n" ); document.write( "0.74x-0.84x=4.2-4.5 \n" ); document.write( "-0.1x=-0.3 \n" ); document.write( "x=3 gal at 74% (2.22) is added to 5 gal at 90%(4.5) to earn 84% of 8 gal(6.72) \n" ); document.write( "check \n" ); document.write( "0.74*3+0.9*5=0.84(5+3) \n" ); document.write( "2.22+4.5=0.84(8) \n" ); document.write( "6.72=6.72 \n" ); document.write( "ok\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |