document.write( "Question 906935: find the length of the tangent (-4,1) on the circle given by the equation x^2+y^2+8x+12y+5=0. \n" ); document.write( "
Algebra.Com's Answer #550102 by Alan3354(69443)\"\" \"About 
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find the length of the tangent (-4,1) on the circle given by the equation x^2+y^2+8x+12y+5=0.
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\n" ); document.write( "Find the center of the circle.
\n" ); document.write( "Put the equation is standard form.
\n" ); document.write( "(x+4)^2 + (y+6)^2 = 47
\n" ); document.write( "--> center at (-4,-6)
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\n" ); document.write( "Move the circle and the point 6 units up and 4 units right.
\n" ); document.write( "Now the circle is x^2 + y^2 = 47 and the point is (0,7)
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\n" ); document.write( "Find the tangent that passes thru (0,7)
\n" ); document.write( "(x,y) is a point on the circle
\n" ); document.write( "The slope of the tangent m1 = (y-7)/x
\n" ); document.write( "The slope of the tangent at any point on the circle m2 = -x/y
\n" ); document.write( "m1 = m2
\n" ); document.write( "(y-7)/x = -x/y
\n" ); document.write( "-x^2 = y^2 - 7y
\n" ); document.write( "x^2 + y^2 = 7y
\n" ); document.write( "x^2 + y^2 = 47
\n" ); document.write( "7y = 47
\n" ); document.write( "y = 47/7
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\n" ); document.write( "\"x+=+sqrt%2847+-+47%5E2%2F7%5E2%29+=+sqrt%2894%29%2F7\"\r
\n" ); document.write( "\n" ); document.write( "One tangent point is (sqrt(94)/7,(47/7))
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\n" ); document.write( "Find the distance between those 2 points.
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