document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=906872>Question 906872</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need an age problem that results to 39 years old and 16 years old :) please </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #550082 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=550082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> jack is 39 years old.<BR>\n" );
document.write( "jill is 16.\r<BR>\n" );
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document.write( "in how many years will jack be 3 times as old as jill?\r<BR>\n" );
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document.write( "solution is as follows:\r<BR>\n" );
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document.write( "x = the number of years.\r<BR>\n" );
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document.write( "39 + x = 3 * 16 which becomes:<BR>\n" );
document.write( "39 + x = 48<BR>\n" );
document.write( "subtract 39 from both sides of the equation to get:<BR>\n" );
document.write( "x = 48 - 39<BR>\n" );
document.write( "solve for x to get x = 9\r<BR>\n" );
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document.write( "39 + 9 = 48<BR>\n" );
document.write( "3 * 16 = 48<BR>\n" );
document.write( "39 + 9 = 3 * 16<BR>\n" );
document.write( "jack will be 3 times as old as jill is today in 9 years.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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