document.write( "Question 906774: The owner of a candy store wants to mix some peanuts worth $2 per pound, some cashews worth $9 per pound, and some Brazil nuts worth $7 per pound to get 50 pounds of a mixture that will sell for $4.70 per pound. She uses 20 fewer pounds of cashews than peanuts. How many pounds of each did she use? \n" ); document.write( "

Algebra.Com's Answer #550075 by josgarithmetic(39617) $\"\"$ $\"About$

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p, c, b for the poundages of peanuts, cashews, brazil nuts.\r
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\n" ); document.write( "\n" ); document.write( " $\"2p%2B9c%2B7b=%284.70%29%2A50\"$ , account for the cost of 50 pound mixture
\n" ); document.write( " $\"p%2Bc%2Bb=50\"$ , account for amount of mixture
\n" ); document.write( " $\"c=p-20\"$ , the described relationship between two of the nuts\r
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\n" ); document.write( "\n" ); document.write( "Simplify the system by first substituting for c, and simplify the two remaining equations which are now using only variables b and p.
\n" ); document.write( "Solve the system. \n" ); document.write( "

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