document.write( "Question 906791: A plane leaves an airport at 3 P.M. At 4 P.M., another plane leaves the same airport traveling in the same direction at a speed that is 150 mph faster than that of the first plane. Four hours after the first plane takes off, the second plane is 250 mi ahead of the first plane. How far did the second plane travel? \n" ); document.write( "
Algebra.Com's Answer #550059 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A plane leaves an airport at 3 P.M. At 4 P.M., another plane leaves the same airport traveling in the same direction at a speed that is 150 mph faster than that of the first plane. Four hours after the first plane takes off, the second plane is 250 mi ahead of the first plane. How far did the second plane travel? \r \n" ); document.write( "\n" ); document.write( "First plane speed = x \n" ); document.write( "second plane speed = x+150\r \n" ); document.write( "\n" ); document.write( "Distance traveled by second plane - distance by first plane = 250 miles\r \n" ); document.write( "\n" ); document.write( "distance traveled by first plane in 4 hours = 4x\r \n" ); document.write( "\n" ); document.write( "distance traveled by second plane = 3(x+150) ( 1 hour later)\r \n" ); document.write( "\n" ); document.write( "3(x+150)-4x=250\r \n" ); document.write( "\n" ); document.write( "3x+450-4x=250\r \n" ); document.write( "\n" ); document.write( "-x=250-450 \n" ); document.write( "-x=-200 \n" ); document.write( "x= 200\r \n" ); document.write( "\n" ); document.write( "speed of first plane = 200 mph \n" ); document.write( "speed of second plane = 200+150 = 350 mph\r \n" ); document.write( "\n" ); document.write( "distance of second plane = 3*350=1050 miles \n" ); document.write( " |