document.write( "Question 906807: How many liters of 60% alcohol solution and 20% alcohol solution must be mixed to obtain 16 liters of 50% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #550056 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! a+b=16, \n" ); document.write( "0.6*a+0.2*b=0.5*16 \n" ); document.write( "a=16-b \n" ); document.write( "0.6*(16-b)+0.2*b=8 \n" ); document.write( "9.6-0.6b+0.2*b=8 \n" ); document.write( "-0.4*b=-1.6 \n" ); document.write( "b=4 \n" ); document.write( "a=16-b \n" ); document.write( "a=12 liter at 60% \n" ); document.write( "b=4 liter at 20% \n" ); document.write( "check \n" ); document.write( "0.6*12+0.2*4=0.5*16 \n" ); document.write( "7.2+0.8=8 \n" ); document.write( "8=8 \n" ); document.write( "ok\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |